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This page describes
the reactions between alkanes and cycloalkanes with the halogens fluorine,
chlorine, bromine and iodine - mainly concentrating on chlorine and bromine.
Alkanes
The reaction between
alkanes and fluorine
This reaction is
explosive even in the cold and dark, and you tend to get carbon and hydrogen
fluoride produced. It is of no particular interest. For example:
The reaction between
alkanes and iodine
Iodine doesn't react
with the alkanes to any extent - at least, under normal lab conditions.
The reactions between
alkanes and chlorine or bromine
There is no reaction
in the dark.
In the presence of a
flame, the reactions are rather like the fluorine one - producing a mixture
of carbon and the hydrogen halide. The violence of the reaction drops
considerably as you go from fluorine to chlorine to bromine.
The interesting
reactions happen in the presence of ultra-violet light (sunlight will do).
These are photochemical reactions, and happen at room
temperature.
We'll look at the
reactions with chlorine. The reactions with bromine are similar, but rather
slower.
Methane and chlorine
Substitution reactions happen in which hydrogen atoms in the methane
are replaced one at a time by chlorine atoms. You end up with a mixture of
chloromethane, dichloromethane, trichloromethane and tetrachloromethane.
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The original mixture
of a colourless and a green gas would produce steamy fumes of hydrogen
chloride and a mist of organic liquids. All of the organic products are
liquid at room temperature with the exception of the chloromethane which is a
gas.
If you were using
bromine, you could either mix methane with bromine vapour, or bubble the
methane through liquid bromine - in either case, exposed to UV light. The
original mixture of gases would, of course, be red-brown rather than green.
You wouldn't choose to
use these reactions as a means of preparing these organic compounds in the
lab because the mixture of products would be too tedious to separate.
The mechanisms for the
reactions are explained on separate pages.
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Larger alkanes and
chlorine
You would again get a
mixture of substitution products, but it is worth just looking briefly at
what happens if only one of the hydrogen atoms gets substituted
(monosubstitution) - just to show that things aren't always as
straightforward as they seem!
For example, with
propane, you could get one of two isomers:
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If chance was the only
factor, you would expect to get 3 times as much of the isomer with the
chlorine on the end. There are 6 hydrogens that could get replaced on the end
carbon atoms compared with only 2 in the middle.
In fact, you get about
the same amount of each of the two isomers.
If you use bromine
instead of chlorine, the great majority of the product is where the bromine
is attached to the centre carbon atom.
The reasons for this
are beyond UK A level chemistry.
Cycloalkanes
The reactions of the cycloalkanes
are generally just the same as the alkanes, with the exception of the very
small ones - particularly cyclopropane.
The extra reactivity
of cyclopropane
In the presence of UV
light, cyclopropane will undergo substitution reactions with chlorine or
bromine just like a non-cyclic alkane. However, it also has the ability to
react in the dark.
In the absence of UV
light, cyclopropane can undergo addition reactions in which the
ring is broken. For example, with bromine, cyclopropane gives 1,3-dibromopropane.
This can still happen
in the presence of light - but you will get substitution reactions as well.
The ring is broken
because cyclopropane suffers badly from ring strain. The bond
angles in the ring are 60° rather than the normal value of about 109.5° when
the carbon makes four single bonds.
The overlap between
the atomic orbitals in forming the carbon-carbon bonds is less good than it
is normally, and there is considerable repulsion between the bonding pairs.
The system becomes more stable if the ring is broken.
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