- Get link
- X
- Other Apps
This page looks at the
reactions of amines as bases. Their basic properties include the reactions
with dilute acids, water and copper(II) ions.
It only deals with
amines where the functional group is not attached directly to a
benzene ring. Aromatic amines such as phenylamine (aniline) are much weaker
bases than the amines discussed on this page and are dealt with separately on
a page specifically about phenylamine. If you are interested in phenylamine,
read this page first and then follow the link at the bottom.
The basic properties
of amines
We are going to have
to use two different definitions of the term "base" in this page.
A base is
|
|
Note: If you aren't familiar with either of these
terms, you should follow this link to a page about theories of acids and
bases.
Use the BACK button
on your browser to return to this page when you are confident about these
terms.
|
|
The easiest way of
looking at the basic properties of amines is to think of an amine as a
modified ammonia molecule. In an amine, one or more of the hydrogen atoms in
ammonia has been replaced by a hydrocarbon group.
Replacing the
hydrogens still leaves the lone pair on the nitrogen unchanged - and it is
the lone pair on the nitrogen that gives ammonia its basic properties. Amines
will therefore behave much the same as ammonia in all cases where the lone
pair is involved.
The reactions of
amines with acids
These are most easily
considered using the Bronsted-Lowry theory of acids and bases - the base is a
hydrogen ion acceptor. We'll do a straight comparison between amines and the
familiar ammonia reactions.
A reminder about the
ammonia reactions
Ammonia reacts with
acids to produce ammonium ions. The ammonia molecule picks up a hydrogen ion
from the acid and attaches it to the lone pair on the nitrogen.
If the reaction is in
solution in water (using a dilute acid), the ammonia takes a hydrogen ion (a
proton) from a hydroxonium ion. (Remember that hydrogen ions present in
solutions of acids in water are carried on water molecules as hydroxonium
ions, H3O+.)
If the acid was
hydrochloric acid, for example, you would end up with a solution containing
ammonium chloride - the chloride ions, of course, coming from the
hydrochloric acid.
You could also write
this last equation as:
. . . but if you do it
this way, you must include the state symbols. If you write H+
on its own, it implies an unattached hydrogen ion - a proton. Such things
don't exist on their own in solution in water.
If the reaction is
happening in the gas state, the ammonia accepts a proton directly from the
hydrogen chloride:
This time you produce
clouds of white solid ammonium chloride.
The corresponding
reactions with amines
The nitrogen lone pair
behaves exactly the same. The fact that one (or more) of the hydrogens in the
ammonia has been replaced by a hydrocarbon group makes no difference.
For example, with
ethylamine:
If the reaction is
done in solution, the amine takes a hydrogen ion from a hydroxonium ion and
forms an ethylammonium ion.
Or:
The solution would
contain ethylammonium chloride or sulphate or whatever.
Alternatively, the
amine will react with hydrogen chloride in the gas state to produce the same
sort of white smoke as ammonia did - but this time of ethylammonium chloride.
These examples have
involved a primary amine. It would make no real difference if you used a
secondary or tertiary one. The equations would just look more complicated.
The product ions from
diethylamine and triethylamine would be diethylammonium ions and
triethylammonium ions respectively.
The reactions of
amines with water
Again, it is easiest
to use the Bronsted-Lowry theory and, again, it is useful to do a straight
comparison with ammonia.
A reminder about the
ammonia reaction with water
Ammonia is a weak base
and takes a hydrogen ion from a water molecule to produce ammonium ions and
hydroxide ions.
However, the ammonia
is only a weak base, and doesn't hang on to the hydrogen ion very
successfully. The reaction is reversible, with the great majority of the
ammonia at any one time present as free ammonia rather than ammonium ions.
The presence of the
hydroxide ions from this reaction makes the solution alkaline.
The corresponding
reaction with amines
The amine still
contains the nitrogen lone pair, and does exactly the same thing.
For example, with
ethylamine, you get ethylammonium ions and hydroxide ions produced.
There is, however, a
difference in the position of equilibrium. Amines are usually stronger bases
than ammonia. (There are exceptions to this, though - particularly if the
amine group is attached directly to a benzene ring.)
|
|
Note: If you want to explore some of the reasons
for the relative strengths of
ammonia and the amines as bases you could follow this link.
UK A level
syllabuses are only concerned with the relative strengths of ammonia and the
primary amines, so that is all you will find on that page.
If you choose to
follow this link, use the BACK button on your browser to return to this page.
|
|
The reactions of
amines with copper(II) ions
Just like ammonia,
amines react with copper(II) ions in two separate stages. In the first step,
we can go on using the Bronsted-Lowry theory (that a base is a hydrogen ion
acceptor). The second stage of the reaction can only be explained in terms of
the Lewis theory (that a base is an electron pair donor).
The reaction between
ammonia and copper(II) ions
Copper(II) sulphate
solution, for example, contains the blue hexaaquacopper(II) ion - [Cu(H2O)6]2+.
In the first stage of
the reaction, the ammonia acts as a Bronsted-Lowry base. With a small amount
of ammonia solution, hydrogen ions are pulled off two water molecules in the
hexaaqua ion.
This produces a
neutral complex - one carrying no charge. If you remove two positively
charged hydrogen ions from a 2+ ion, then obviously there isn't going to be
any charge left on the ion.
Because of the lack of
charge, the neutral complex isn't soluble in water, and so you get a pale
blue precipitate.
This precipitate is
often written as Cu(OH)2 and called copper(II) hydroxide. The
reaction is reversible because ammonia is only a weak base.
That precipitate
dissolves if you add an excess of ammonia solution, giving a deep blue
solution.
The ammonia replaces
four of the water molecules around the copper to give tetraamminediaquacopper(II)
ions. The ammonia uses its lone pair to form a co-ordinate covalent bond
(dative covalent bond) with the copper. It is acting as an electron pair
donor - a Lewis base.
|
|
Note: You might wonder why this second equation is
given starting from the original hexaaqua ion rather than the neutral
complex. Explaining why the precipitate redissolves is quite complicated. You
will find a lot more explanations about the reactions between
hexaaqua ions and ammonia solution in the inorganic section of this site if you are interested.
(Important:
The inorganic section describes ammonia acting as a ligand
in the second stage of the reaction. It is acting as a ligand because it has
a lone pair of electrons - in other words, because it is a Lewis base.)
Use the BACK button
(or HISTORY file or GO menu) on your browser to return to this page.
|
|
The colour changes
are:
The corresponding
reaction with amines
The small primary
amines behave in exactly the same way as ammonia. There will, however, be
slight differences in the shades of blue that you get during the reactions.
Taking methylamine as
an example:
With a small amount of
methylamine solution you will get a pale blue precipitate of the same neutral
complex as with ammonia. All that is happening is that the methylamine is
pulling hydrogen ions off the attached water molecules.
With more methylamine solution
the precipitate redissolves to give a deep blue solution - just as in the
ammonia case. The amine replaces four of the water molecules around the
copper.
As the amines get
bigger and more bulky, the formula of the final product may change - simply
because it is impossible to fit four large amine molecules and two water
molecules around the copper atom.
|
Comments
Post a Comment