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This page summarises
the reactions of amines as nucleophiles. This includes their reactions with
halogenoalkanes (haloalkanes or alkyl halides), with acyl chlorides (acid
chlorides) and with acid anhydrides.
All of these reactions
are dealt with in detail on other pages and you will find links to all of
these.
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Note: If you are mainly interested in phenylamine
(aniline), its reactions are summarised in another section. You will find a
link at the bottom of this page. It might be a good idea to read the current
page first, though.
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The nucleophilic
properties of amines
Why do amines act as
nucleophiles?
A nucleophile is
something which is attracted to, and then attacks, a positive or slightly
positive part of another molecule or ion.
All amines contain an
active lone pair of electrons on the very electronegative nitrogen atom. It
is these electrons which are attracted to positive parts of other molecules
or ions.
The reactions of
primary amines with halogenoalkanes
You get a complicated
series of reactions on heating to give a mixture of products - probably one
of the most confusing sets of reactions you will meet at this level. The
products of the reactions include secondary and tertiary amines and their
salts, and quaternary ammonium salts.
Making secondary
amines and their salts
In the first stage of
the reaction, you get the salt of a secondary amine formed. For example if
you started with ethylamine and bromoethane, you would get diethylammonium
bromide
In the presence of
excess ethylamine in the mixture, there is the possibility of a reversible
reaction. The ethylamine removes a hydrogen from the diethylammonium ion to
give free diethylamine - a secondary amine.
Making tertiary amines
and their salts
But it doesn't stop
here! The diethylamine also reacts with bromoethane - in the same two stages
as before. This is where the reaction would start if you reacted a secondary
amine with a halogenoalkane.
In the first stage,
you get triethylammonium bromide.
There is again the
possibility of a reversible reaction between this salt and excess ethylamine
in the mixture.
The ethylamine removes
a hydrogen ion from the triethylammonium ion to leave a tertiary amine -
triethylamine.
Making a quaternary
ammonium salt
The final stage! The
triethylamine reacts with bromoethane to give tetraethylammonium bromide - a
quaternary ammonium salt (one in which all four hydrogens have been replaced
by alkyl groups).
This time there isn't
any hydrogen left on the nitrogen to be removed. The reaction stops here.
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Note: You will find this reaction explored in the
page about the reactions between
halogenoalkanes and ammonia - although in that case starting from bromoethane and
ammonia. It would be useful to read that in order to compare the ammonia
reactions with the amine reactions. The only real difference is that the
hydrogen ions are removed by an amine in the case we are currently looking at
rather than ammonia on the other page.
You will find a
further link to the mechanisms for these reactions on that page. If you
follow that link it will take you to quite a number of pages exploring these
reactions. You will need to spend some time on these if you really want to
understand this. However, understanding the reactions in terms of their
mechanisms means that you can work out what happens if you need to rather
than trying to remember all this (a fairly pointless and soul-destroying
exercise!).
Use the BACK button
(or HISTORY file or GO menu) on your browser to return to this page.
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The reactions of
amines with acyl chlorides (acid chlorides)
We'll take the
reaction between methylamine and ethanoyl chloride as typical.
If you add
concentrated methylamine solution to ethanoyl chloride, there is a violent
reaction in the cold. N-methylethanamide and methylammonium chloride are
formed - partly as a white solid mixture, and partly in solution.
The overall equation
is:
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Note: This reaction (and the corresponding one
with ammonia) is discussed in detail on a page about the reactions between acyl chlorides and
nitrogen compounds. You will also find
a link to the introduction to the mechanisms for these reactions on that
page. If you want to go straight to the mechanism for the amine
reaction, you could follow
this link.
Use the BACK button
on your browser to return to this page.
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The reactions of
amines with acid anhydrides
These reactions are
chemically similar to those between amines and acyl chlorides, but they are
much slower, needing heat.
Taking the reaction
between methylamine and ethanoic anhydride as typical:
The product is
N-methylethanamide (as with ethanoyl chloride), but this time the other
product is methylammonium ethanoate rather than methylammonium chloride.
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Note: I have shown the ionic nature of the
methylammonium ethanoate this time because it isn't otherwise obvious how
everything joins up. Methylammonium chloride is, of course, also ionic. I
have also reversed the formula for the methylammonium ion so that the
positive charge is close to the negative charge on the ethanoate ion.
This reaction (and
the corresponding one with ammonia) is discussed in detail on a page about
the reactions between acid anhydrides and
nitrogen compounds. This is quite
difficult stuff - it would pay you to read the whole of that page fairly
carefully if you really want to understand what's going on.
Use the BACK button
on your browser to return to this page.
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