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This page looks at the
reactions of nitrous acid with aliphatic amines (those where the amine group
isn't attached directly to a benzene ring). Nitrous acid is properly called
nitric(III) acid, but that name isn't commonly used.
Reactions between
nitrous acid and aromatic amines like phenylamine (where the -NH2
group is attached directly to a benzene ring) are dealt with elsewhere.
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Note: Unless you want to compare the reactions of
aliphatic and aromatic amines with nitrous acid, if you are interested mainly
in the reactions of
phenylamine with nitrous acid, it would pay you to go straight to this page.
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Testing for the
various types of amines
Background
The reaction between
amines and nitrous acid was used in the past as a very neat way of
distinguishing between primary, secondary and tertiary amines. However, the
product with a secondary amine is a powerful carcinogen, and so this reaction
is no longer carried out at this level.
Nitrous acid, HNO2,
(sometimes written as HONO to show its structure) is unstable and is always
prepared in situ.
It is usually made by
reacting a solution containing sodium or potassium nitrite (sodium or
potassium nitrate(III)) with hydrochloric acid.
Nitrous acid is a weak
acid and so you get the reaction:
Because nitrous acid
is a weak acid, the position of equilibrium lies well the right.
In each of the
following reactions, the amine would be acidified with hydrochloric acid and
a solution of sodium or potassium nitrite added. The acid and the nitrite
form nitrous acid which then reacts with the amine.
Primary amines and
nitrous acid
The main observation
is a burst of colourless, odourless gas. Nitrogen is given off.
Unfortunately, there
is no single clear-cut equation that you can quote for this. You get lots of
different organic products. For example, amongst the products you get an
alcohol where the -NH2 group has been replaced by OH. If you want
a single equation, you could quote (taking 1-aminopropane as an example):
. . . but the
propan-1-ol will be only one product among many - including propan-2-ol,
propene, 1-chloropropane, 2-chloropropane and others.
The nitrogen, however,
is given off in quantities exactly as suggested by the equation. By measuring
the amount of nitrogen produced, you could use this reaction to work out the
amount of amine present in the solution.
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Note: The reason for the complexity lies in how
the reaction happens. In the first instance, you get a diazonium ion
formed - for example, CH3CH2CH2N2+.
Unless the -N2+ group is attached directly to a benzene
ring, these ions are very unstable and fall apart immediately to give
nitrogen gas and a carbocation (carbonium ion) - in this example, CH3CH2CH2+.
It is rearrangements
and reactions of this ion which lead to the mess of products.
With aromatic amines
like phenylamine (aniline) the diazonium ion formed is much more stable. If
you are interested in reactions of diazonium
ions (but only in the
context of amines like phenylamine), follow this link.
Use the BACK button
on your browser if you want to return to this page later.
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Secondary amines and
nitrous acid
This time there isn't
any gas produced. Instead, you get a yellow oil called a nitrosamine. These
compounds are powerful carcinogens - avoid them!
For example:
Tertiary amines and
nitrous acid
Again, a quite
different result. This time, nothing visually interesting happens - you are
left with a colourless solution.
All that has happened
is that the amine has formed an ion by reacting with the acid present. With
trimethylamine, for example, you would get a trimethylammonium ion, (CH3)3NH+.
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Note: Textbooks often suggest the formation of a
salt such as trimethylammonium nitrite. This is actually a bit misleading.
The solution will contain trimethylammonium ions and nitrite ions and also
chloride ions from the hydrochloric acid. There isn't any reason why the
trimethylammonium ions should be thought of as combining with the nitrite
ions in some way rather than with the chloride ions. They are all just
free-swimming ions, milling around in the solution.
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