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This page mainly looks at the reactions of the Group 1
elements (lithium, sodium, potassium, rubidium and caesium) with oxygen -
including the simple reactions of the various kinds of oxides formed. It also
deals very briefly with the reactions of the elements with chlorine.
The Reactions with Air or Oxygen
General
These are all very reactive metals and have to be stored
out of contact with air to prevent their oxidation. Reactivity increases as
you go down the Group.
Lithium, sodium and potassium are stored in oil. (Lithium
in fact floats on the oil, but there will be enough oil coating it to give it
some protection. It is, anyway, less reactive than the rest of the Group.)
Rubidium and caesium are normally stored in sealed glass
tubes to prevent air getting at them. They are stored either in a vacuum or
in an inert atmosphere of, say, argon. The tubes are broken open when the
metal is used.
Depending on how far down the Group you are, different
kinds of oxide are formed when the metals burn (details below). Reaction with
oxygen is just a more dramatic version of the reaction with air.
Lithium is unique in the Group because it also reacts with
the nitrogen in the air to form lithium nitride (again, see below).
Details for the individual metals
Lithium
Lithium burns with a strongly red-tinged flame if heated
in air. It reacts with oxygen in the air to give white lithium oxide. With
pure oxygen, the flame would simply be more intense.
For the record, it also reacts with the nitrogen in the
air to give lithium nitride. Lithium is the only element in this Group to
form a nitride in this way.
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Note: You will find the reason why lithium
forms a nitride on the page about reactions of Group 2
elements with air or oxygen. You will find what you want about 3/4 of the
way down that page.
Lithium's reactions are often rather like those of the
Group 2 metals. There is a diagonal relationship between lithium and
magnesium. You will find this discussed on the page about electronegativity.
Use the BACK button on your browser to return to this page
from either of these links.
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Sodium
Small pieces of sodium burn in air with often little more
than an orange glow. Using larger amounts of sodium or burning it in oxygen
gives a strong orange flame. You get a white solid mixture of sodium oxide
and sodium peroxide.
The equation for the formation of the simple oxide is just
like the lithium one.
The peroxide equation is:
Potassium
Small pieces of potassium heated in air tend to just melt
and turn instantly into a mixture of potassium peroxide and potassium
superoxide without any flame being seen. Larger pieces of potassium burn with
a lilac flame.
The equation for the formation of the peroxide is just
like the sodium one above:
. . . and for the superoxide:
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Note: Potassium peroxide and superoxide are
described as being somewhere between yellow and orange depending on what
source you look at. I have a bit of a problem with this, because over my
teaching career I have heated potassium in air many times and, if memory
serves correctly, it always leaves a greyish white film on the bit of
porcelain you are heating it on. I don't recall ever seeing it yellow or
orange!
The formula for a peroxide doesn't look too stange,
because most people are familiar with the similar formula for hydrogen
peroxide. The formula for a superoxide always looks wrong! There is more
about these oxides later on.
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Rubidium and caesium
Both metals catch fire in air and produce superoxides, RbO2
and CsO2. The equations are the same as the equivalent potassium
one.
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Note: In a lifetime in teaching chemistry, I
have never actually handled (or even seen in real life!) either of these
metals. I haven't even seen video or film clips of them being burnt. That
means that I don't have much confidence in this next bit.
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Both superoxides are described in most sources as being
either orange or yellow. One major web source describes rubidium superoxide
as being dark brown on one page and orange on another!
I don't know what the flames look like either. You can't
necessarily be sure that the flame that a metal burns with will be the same
as the flame colour of its compounds.
Why are different oxides formed as you go down the
Group?
The more complicated ions aren't stable in the presence of
a small positive ion. Consider the peroxide ion, for example.
The peroxide ion, O22- looks like
this:
The covalent bond between the two oxygen atoms is
relatively weak.
Now imagine bringing a small positive ion close to the
peroxide ion. Electrons in the peroxide ion will be strongly attracted
towards the positive ion. This is then well on the way to forming a simple
oxide ion if the right-hand oxygen atom (as drawn below) breaks off.
We say that the positive ion polarises the
negative ion. This works best if the positive ion is small and highly charged
- if it has a high charge density.
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Note: A high charge density simply means that
you have a lot of charge packed into a small volume.
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Even though it only has one charge, the lithium ion at the
top of the Group is so small and has such a high charge density that any
peroxide ion near it falls to pieces to give an oxide and oxygen. As you go
down the Group to sodium and potassium the positive ions get bigger and they
don't have so much effect on the peroxide ion.
The superoxide ions are even more easily pulled apart, and
these are only stable in the presence of the big ions towards the bottom of
the Group.
So why do any of the metals form the more complicated
oxides? It is a matter of energetics.
In the presence of sufficient oxygen, they produce the
compound whose formation gives out most energy. That gives the most stable
compound.
The amount of heat evolved per mole of rubidium in forming
its various oxides is:
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Note: These figures are based on a thermodynamic
properties table from Gazi University in Turkey. It was the only place I
could track down a value for the enthalpy of formation of rubidium
superoxide. The enthalpy of formation values for rubidium oxide and peroxide
have been divided by two to give results per mole of rubidium in order to
make them comparable with the superoxide value.
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The values for the various potassium oxides show exactly
the same trends. As long as you have enough oxygen, forming the peroxide
releases more energy per mole of metal than forming the simple oxide. Forming
the superoxide releases even more.
I assume the same thing to be true of the caesium oxides,
although I couldn't find all the figures to be able to check it.
Summary
Forming the more complicated oxides from the metals
releases more energy and makes the system more energetically stable. BUT . .
. this only works for the metals in the lower half of the Group where the
metal ions are big and have a low charge density.
At the top of the Group, the small ions with a higher
charge density tend to polarise the more complicated oxide ions to the point
of destruction.
Reactions of the Oxides
The simple oxides, X2O
Reaction with water
These are simple basic oxides, reacting with water to give
the metal hydroxide.
For example, lithium oxide reacts with water to give a
colourless solution of lithium hydroxide.
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Note: I'm going to use "X" for all
the rest of the equations in this section. There is no difference between the
equations for the various elements in the Group whichever metal oxide (or
peroxide or superoxide) you are using.
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Reaction with dilute acids
These simple oxides all react with an acid to give a salt
and water. For example, sodium oxide will react with dilute hydrochloric acid
to give colourless sodium chloride solution and water.
The peroxides, X2O2
Reaction with water
If the reaction is done ice cold (and the temperature
controlled so that it doesn't rise even though these reactions are strongly
exothermic), a solution of the metal hydroxide and hydrogen peroxide is
formed.
If the temperature increases (as it inevitably will unless
the peroxide is added to water very, very, very slowly!), the hydrogen
peroxide produced decomposes into water and oxygen. The reaction can be very
violent overall.
Reaction with dilute acids
These reactions are even more exothermic than the ones
with water. A solution containing a salt and hydrogen peroxide is formed. The
hydrogen peroxide will decompose to give water and oxygen if the temperature
rises - again, it is almost impossible to avoid this. Another potentially
violent reaction!
The superoxides, XO2
Reaction with water
This time, a solution of the metal hydroxide and hydrogen
peroxide is formed, but oxygen gas is given off as well. Once again, these
are strongly exothermic reactions and the heat produced will inevitably
decompose the hydrogen peroxide to water and more oxygen. Again violent!
Reaction with dilute acids
Again, these reactions are even more exothermic than the
ones with water. A solution containing a salt and hydrogen peroxide is formed
together with oxygen gas. The hydrogen peroxide will again decompose to give
water and oxygen as the temperature rises. Violent!
The Reactions of the elements with Chlorine
This is included on this page because of the similarity in
appearance between the reactions of the Group 1 metals with chlorine and with
oxygen.
Sodium, for example, burns with an intense orange flame in
chlorine in exactly the same way that it does in pure oxygen. The rest also
behave the same in both gases.
In each case, there is a white solid residue which is the
simple chloride, XCl. There is nothing in any way complicated about these
reactions!
Where would you like to go now?
© Jim Clark 2005
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